I need help with this because I don’t get it so if you can help me please let me know

Answer:Step-by-step explanation:(1)[tex]\triangle ACD[/tex] has the constant ratio of the sides. AB/AC = AE/EDSo solving for x is simple:AB/AC = 6/2 = 3 = AE/x = 9/x9/x = 39 = 3xx = 3(2)[tex]\triangle GIF[/tex] is similar to [tex]\triangle IJH[/tex]To be similar, the ratio between the respective sides must be equal =>IJ/IF = IH/IG = HJ/GF.So we plug in the value of the sides.10/5 = x/12x/12 = 10/5x/12 = 2x = 24(3)I don't understand the picture (Sorry)(4)[tex]\triangle RPS[\tex] is similar to [tex]\triangle QPT[/tex]Which implies:PQ/QR = QT/RS5/7 = 4/x[4/x = 5/7] * x4 = (5/7)xx = 4 * 7/5 = 28/5 = 5 3/5