Jolyn, a golfer, claims that her drive distance is not equal to 222 meters, on average. Several of her friends do not believe her, so she decides to do a hypothesis test, at a 5% significance level, to persuade them. She hits 11 drives. The mean distance of the sample drives is 218 meters. Jolyn knows from experience that the standard deviation for her drive distance is 14 meters. H0: μ=222; Ha: μ≠222 α=0.05 (significance level) What is the test statistic (z-score) of this one-mean hypothesis test, rounded to two decimal places? Provide your answer below:
Accepted Solution
A:
Answer:0.29Step-by-step explanation:z-score is given by the formula:z=(μ-M)/σ where μ is the hypothesis drive distance, which is 222M is the mean sample drive distanceσ is the standard deviation of the sample drive distanceTherefore z=(222-218)/14≈0.29