The chance that two people both have three repeat sequences at location A is 1 in 500. The chance that two people have four repeat sequences at location B is 1 in 800. What is the probability that two people have the same number of repeats in both location A and location B
Accepted Solution
A:
Answer: Probability that two people have the same number of repeats in both location A and location B is [tex]\dfrac{1}{40000Step-by-step explanation:Since we have given that Probability that two people both have 3 repeat sequences at location A = [tex]\dfrac{1}{500}[/tex]Probability that two people both have 4 repeat sequences at location B = [tex]\dfrac{1}{800}[/tex]P(A) =[tex]\dfrac{1}{500}[/tex] and P(B) = [tex]\dfrac{1}{800}[/tex]Since A and B are independent events.According to question, [tex]P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\dfrac{1}{500}\times \dfrac{1}{800}\\\\P(A\cap B)=\dfrac{1}{40000}[/tex]Hence, probability that two people have the same number of repeats in both location A and location B is [tex]\dfrac{1}{40000}[/tex]